Optimal. Leaf size=194 \[ -\frac{\left (-2 c \left (a d^2-c e^2\right )+b^2 d^2-2 b c d e\right ) \tanh ^{-1}\left (\frac{2 a x+b}{\sqrt{b^2-4 a c}}\right )}{\sqrt{b^2-4 a c} \left (a d^2-e (b d-c e)\right )^2}-\frac{d^2}{e (d+e x) \left (a d^2-b d e+c e^2\right )}-\frac{d (b d-2 c e) \log \left (a x^2+b x+c\right )}{2 \left (a d^2-e (b d-c e)\right )^2}+\frac{d (b d-2 c e) \log (d+e x)}{\left (a d^2-e (b d-c e)\right )^2} \]
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Rubi [A] time = 0.558972, antiderivative size = 194, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.273 \[ -\frac{\left (-2 c \left (a d^2-c e^2\right )+b^2 d^2-2 b c d e\right ) \tanh ^{-1}\left (\frac{2 a x+b}{\sqrt{b^2-4 a c}}\right )}{\sqrt{b^2-4 a c} \left (a d^2-e (b d-c e)\right )^2}-\frac{d^2}{e (d+e x) \left (a d^2-b d e+c e^2\right )}-\frac{d (b d-2 c e) \log \left (a x^2+b x+c\right )}{2 \left (a d^2-e (b d-c e)\right )^2}+\frac{d (b d-2 c e) \log (d+e x)}{\left (a d^2-e (b d-c e)\right )^2} \]
Antiderivative was successfully verified.
[In] Int[1/((a + c/x^2 + b/x)*(d + e*x)^2),x]
[Out]
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Rubi in Sympy [A] time = 146.522, size = 177, normalized size = 0.91 \[ \frac{d \left (b d - 2 c e\right ) \log{\left (\frac{d}{x} + e \right )}}{\left (a d^{2} - b d e + c e^{2}\right )^{2}} - \frac{d \left (b d - 2 c e\right ) \log{\left (a + \frac{b}{x} + \frac{c}{x^{2}} \right )}}{2 \left (a d^{2} - b d e + c e^{2}\right )^{2}} + \frac{d}{\left (\frac{d}{x} + e\right ) \left (a d^{2} - b d e + c e^{2}\right )} + \frac{\left (- 2 a c d^{2} + b^{2} d^{2} - 2 b c d e + 2 c^{2} e^{2}\right ) \operatorname{atanh}{\left (\frac{b + \frac{2 c}{x}}{\sqrt{- 4 a c + b^{2}}} \right )}}{\sqrt{- 4 a c + b^{2}} \left (a d^{2} - b d e + c e^{2}\right )^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(1/(a+c/x**2+b/x)/(e*x+d)**2,x)
[Out]
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Mathematica [A] time = 0.406467, size = 159, normalized size = 0.82 \[ \frac{\frac{2 \left (2 c \left (c e^2-a d^2\right )+b^2 d^2-2 b c d e\right ) \tan ^{-1}\left (\frac{2 a x+b}{\sqrt{4 a c-b^2}}\right )}{\sqrt{4 a c-b^2}}-\frac{2 d^2 \left (a d^2+e (c e-b d)\right )}{e (d+e x)}-d (b d-2 c e) \log (x (a x+b)+c)+2 d (b d-2 c e) \log (d+e x)}{2 \left (a d^2+e (c e-b d)\right )^2} \]
Antiderivative was successfully verified.
[In] Integrate[1/((a + c/x^2 + b/x)*(d + e*x)^2),x]
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Maple [B] time = 0.013, size = 389, normalized size = 2. \[ -{\frac{{d}^{2}}{ \left ( a{d}^{2}-bde+{e}^{2}c \right ) e \left ( ex+d \right ) }}+{\frac{{d}^{2}\ln \left ( ex+d \right ) b}{ \left ( a{d}^{2}-bde+{e}^{2}c \right ) ^{2}}}-2\,{\frac{d\ln \left ( ex+d \right ) ce}{ \left ( a{d}^{2}-bde+{e}^{2}c \right ) ^{2}}}-{\frac{\ln \left ( a{x}^{2}+bx+c \right ) b{d}^{2}}{2\, \left ( a{d}^{2}-bde+{e}^{2}c \right ) ^{2}}}+{\frac{\ln \left ( a{x}^{2}+bx+c \right ) cde}{ \left ( a{d}^{2}-bde+{e}^{2}c \right ) ^{2}}}-2\,{\frac{ac{d}^{2}}{ \left ( a{d}^{2}-bde+{e}^{2}c \right ) ^{2}\sqrt{4\,ac-{b}^{2}}}\arctan \left ({\frac{2\,ax+b}{\sqrt{4\,ac-{b}^{2}}}} \right ) }+{\frac{{b}^{2}{d}^{2}}{ \left ( a{d}^{2}-bde+{e}^{2}c \right ) ^{2}}\arctan \left ({(2\,ax+b){\frac{1}{\sqrt{4\,ac-{b}^{2}}}}} \right ){\frac{1}{\sqrt{4\,ac-{b}^{2}}}}}-2\,{\frac{bcde}{ \left ( a{d}^{2}-bde+{e}^{2}c \right ) ^{2}\sqrt{4\,ac-{b}^{2}}}\arctan \left ({\frac{2\,ax+b}{\sqrt{4\,ac-{b}^{2}}}} \right ) }+2\,{\frac{{c}^{2}{e}^{2}}{ \left ( a{d}^{2}-bde+{e}^{2}c \right ) ^{2}\sqrt{4\,ac-{b}^{2}}}\arctan \left ({\frac{2\,ax+b}{\sqrt{4\,ac-{b}^{2}}}} \right ) } \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(1/(a+c/x^2+b/x)/(e*x+d)^2,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((e*x + d)^2*(a + b/x + c/x^2)),x, algorithm="maxima")
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Fricas [A] time = 6.04516, size = 1, normalized size = 0.01 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((e*x + d)^2*(a + b/x + c/x^2)),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/(a+c/x**2+b/x)/(e*x+d)**2,x)
[Out]
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GIAC/XCAS [A] time = 0.273423, size = 455, normalized size = 2.35 \[ -\frac{{\left (b^{2} d^{2} e^{2} - 2 \, a c d^{2} e^{2} - 2 \, b c d e^{3} + 2 \, c^{2} e^{4}\right )} \arctan \left (-\frac{{\left (2 \, a d - \frac{2 \, a d^{2}}{x e + d} - b e + \frac{2 \, b d e}{x e + d} - \frac{2 \, c e^{2}}{x e + d}\right )} e^{\left (-1\right )}}{\sqrt{-b^{2} + 4 \, a c}}\right ) e^{\left (-2\right )}}{{\left (a^{2} d^{4} - 2 \, a b d^{3} e + b^{2} d^{2} e^{2} + 2 \, a c d^{2} e^{2} - 2 \, b c d e^{3} + c^{2} e^{4}\right )} \sqrt{-b^{2} + 4 \, a c}} - \frac{d^{2} e}{{\left (a d^{2} e^{2} - b d e^{3} + c e^{4}\right )}{\left (x e + d\right )}} - \frac{{\left (b d^{2} - 2 \, c d e\right )}{\rm ln}\left (-a + \frac{2 \, a d}{x e + d} - \frac{a d^{2}}{{\left (x e + d\right )}^{2}} - \frac{b e}{x e + d} + \frac{b d e}{{\left (x e + d\right )}^{2}} - \frac{c e^{2}}{{\left (x e + d\right )}^{2}}\right )}{2 \,{\left (a^{2} d^{4} - 2 \, a b d^{3} e + b^{2} d^{2} e^{2} + 2 \, a c d^{2} e^{2} - 2 \, b c d e^{3} + c^{2} e^{4}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((e*x + d)^2*(a + b/x + c/x^2)),x, algorithm="giac")
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